Answer: Ok, first start writing our movement equation.
First our acceleration will be the gravity; so a= g
integrating we can obtain the velocity v= g*t + v₀
where v₀ depends on if we trhow the egg upsides or downsides, being the positive direction downsides.
after, the position will be r =
+ v₀*t - 12m
where the -12m is because you are upside a building.
first case: straight down with speed 11m/s
so the velocity is positive
then, if we do
+ 11*t - 12m = 0 and with bashkara obtain the positive root for the time t=1.6 seconds
putting this on our velocity equation you will get v = 10*1.6 + 11 = 27m/s is the velocity of the egg when it hits the ground.
for the other case, our equation will have the form of:
- 11*t - 12m = 0
and the positive root of the time is: t = 3 seconds.
putting it in the velocity equation gives you v= 10*3 - 11 = 29m/s
which is bigger than the first case, so the egg hits the ground with more velocity, ence more energy.