Question

The flywheel of a steam engine runs with a constant angular speed of 158 rev/min. When steam is shut off, the friction of the bearings and the air brings the wheel to rest in 2.6 h. What is the magnitude of the constant angular acceleration of the wheel in rev/min^2? Do not enter the units.

Answer 1

α=1.013rev/min^2

Step-by-step explanation:

Wo=initial angular speed=158rev/min

t=time=2.6h=156min

Wf=final angular speed=0rev /min , this happens because in the end the wheel stops

this is a circular motion with uniform acceleration therefore we can use the following equation

α=angular aceleration=(Wf-Wo)/t

α=(0-158)/156=1.013rev/min^2