Question

Describe the location of the sum, relative to p, on a number line
P+(-2)

Answer 1

The sum of p + (-2) will always be located to the left of p on a number line.

To describe the location of the sum P+(−2) on a number line, you would start at the point represented by

P and then move 2 units to the left.

This is because adding a negative number is equivalent to moving to the left on the number line.

For example, if P is located at the number 5 on the number line, then

P+(−2) would be located at 5−2=3.

So, the sum is 3 units to the left of the point P on the number line.

Answer 2

The location of the sum is 2 units before P (left to P)

Explanation:

* Lets describe the number line

- A number line is a horizontal straight line with numbers placed at

an equal units

- A number line can be extended infinitely to the left and to the right

- A number line represents both positive and negative integers

- The numbers come on it from left to right

- The negative numbers come on the left of zero and the positive

numbers come on the right of zero

- Ex: -5 , -4 , -3 , -2 , -1 , 0 , 1 , 2 , 3 , 4 , 5 part of the numbers on the

number line

- To add numbers on the number line we start from first number of

the addition and if this number is added by a positive number we

go to right , if the number is added by a negative number

we go to left

- Ex: 5 + 3 ⇒ go from 5 to the right 3 units, then your position is at 8

2 + (-3) ⇒ go from 2 to the left 3 units then your position is at -1

* Now lets solve the problem

- The sum of P + (-2)

∵ Your location is P

∵ You will add P by (-2)

- Negative number means you go to the left

∴ Your position will be before P by two units

∴ The location of the sum is 2 units before P (left to P)