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A 2-g string that is 0.79 m long is fixed at both ends and is under tension. This string produces a 500-Hz tone when it vibrates in the third harmonic. The speed of sound in air is 344 m/s. The tension in the string, in is closest to __________

User NicolasW
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1 Answer

2 votes

Answer:


T = 175.6 N

Step-by-step explanation:

As we know that string is vibrating in third harmonic

So we will have


L = 3(\lambda)/(2)

so we have


0.79 = (3)/(2)\lambda

so we have


\lambda = (2)/(3)(0.79)


\lambda = 0.527

we know that frequency of the wave is given as

f = 500 Hz

now we know that

speed of the wave is


v = frequency * wavelength


v = (500)(0.527)


v = 263.3 m/s

now we have


v = \sqrt{(T)/(m/L)}

so we have


263.3 \sqrt{(T)/((0.002/0.79))}


T = 175.6 N

User Amir Gorji
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