Question

Find two consecutive odd integers such that 77 more than the lesser is six times the greater.

The lesser consecutive odd integer is _ and the greater consecutive odd integer is _

Answer 1

To find the consecutive odd integers, we need to let x represent the lesser odd integer and solve the equation x + 77 = 6(x+2). The solution is x = 13, so the lesser odd integer is 13 and the greater odd integer is 15.

Step-by-step explanation:

Let's assume that the lesser consecutive odd integer is x and the greater consecutive odd integer is x+2.

According to the given information, 77 added to the lesser consecutive odd integer is six times the greater consecutive odd integer:

x + 77 = 6(x+2)

Solve the equation:

1. Distribute the 6 on the right side: x + 77 = 6x + 12
2. Subtract x from both sides: 77 = 5x + 12
3. Subtract 12 from both sides: 65 = 5x
4. Divide both sides by 5: 13 = x

The lesser consecutive odd integer is 13 and the greater consecutive odd integer is 15.

Answer 2

The answer to your question is : number 1 = 13 number 2 = 15

Step-by-step explanation:

# 1 = 2n +1

# 2 = 2n +3

Conditions:

2n + 1 + 77 = 6(2n + 3)

Simplify 2n + 78 = 12 n + 18

Solve it for n 12n - 2n = 78 -18

10n = 60

n = 60/10

n = 6

But

# 1 = 2n + 1 = 2(6) + 1 = 12 + 1 = 13

# 2 = 2n + 3 = 2(6) + 3 = 12 + 3 = 15