Answer:
1.336 m
Step-by-step explanation:
q = - 3.77 micro C at y = 0 m
Q = - 4.92 micro C at y = 2.86176 m
Let the electric field is zero at P which is at a distance y from origin.
Electric field at P due to q is equal to the electric field at P due to Q.
![E_(q)=E_(Q)](https://img.qammunity.org/2020/formulas/physics/high-school/p1cox6a4ajs08k5xxcbac5w6am9nlfldi4.png)
![(kq)/(OP^(2))=(kQ)/(AP^(2))](https://img.qammunity.org/2020/formulas/physics/high-school/ot70bz2yjop6ei996o0jh0deai3pr5ba4u.png)
![(3.77)/(y^(2))=(4.92)/(\left ( 2.86176-y \right )^(2))](https://img.qammunity.org/2020/formulas/physics/high-school/iu5vrf7ezjmuwilk7bpjwc44vxq3m3a5fd.png)
![(\left ( 2.86176-y \right ))/(y)}=1.142](https://img.qammunity.org/2020/formulas/physics/high-school/gh5iyprziks9cfrz74rfoen2y54lgpdscr.png)
2.86176 - y = 1.142 y
2.142 y = 2.86176
y = 1.336 m
Thus, the electric field is zero at y = 1.336 m.