Question

A telephone pole guy-wire has an angle of elevation of 35° with respect to the ground. The force of tension in the guy-wire is 120 lb. Find the horizontal and vertical components of the force of tension. (Round to the nearest integer.)

Answer 1

98 lb, 69 lb

Step-by-step explanation:

Tension in wire, T = 120 lb

Angle made with the horizontal, θ = 35°

The horizontal component is given by

`T_(x)=T Cos35`

`T_(x)=120 Cos35=98.3 lb`

`T_(x)=98 lb`

The vertical component is given by

`T_(y)=T Sin35`

`T_(y)=120 Sin35=68.8 lb`

`T_(y)=69 lb`

Thus, the horizontal component of tension is given by 98 lb and the vertical component of tension is given by 69 lb.

Answer 2

Fx = 98 lb

Fy = 69 lb

Step-by-step explanation:

We can see it in the pic