Answer:
The required expression is y = 1.4 - 0.05x
Explanation:
Consider the provided information.
Food mix A contains 2% fat and food mix B contains 7% fat.
Let x kilograms of food A are used, in a 20-kilogram mixture.
Thus, 20 - x kilograms of food B are used, in a 20-kilogram mixture.
Now It is given that A contains 2% fat and food mix B contains 7% fat.
2% and 7% can be written as 0.02 and 0.07 respectively. Let represent the total fat with y.
Thus, the required expression is:
y = 2% (x) + 7% (20 - x)
y = 0.02 (x) + 0.07 (20 - x)
y = 0.02x + 1.4 - 0.07x
y = 1.4 - 0.05x
Hence, the required expression is y = 1.4 - 0.05x