Question

Write a method which will take one number as an argument. (Feel free to use static method or instance method) Given a input number (integer) print the digits of the number. You must use while loop and modulus operator. This program must work for any positive integer. Negative integers are not cons idered as inputs.

Answer 1

// here is code in java.

import java.util.*;

// class definition

class Main

{

// method that return the digits of number

public static void dig(int num)

{

// while loop

while(num>0)

{

// print the digits

System.out.println(num%10);

num=num/10;

}

}

//driver method

public static void main (String[] args) throws java.lang.Exception

{

try{

// scanner object to read input string

Scanner s=new Scanner(System.in);

// variable

int num;

System.out.print("please enter the number: ");

//read the number

num=s.nextInt();

// validate the input, read a positive number only

while(num<=0)

{

System.out.print("enter a positive number only:");

num=s.nextInt();

}

System.out.println("digit of number are:");

// call the function

dig(num);

}catch(Exception ex){

return;}

}

}

Step-by-step explanation:

Read a number from user and assign it to variable "num".Check if it is positive or not.If input is negative then ask user to again enter a positive number till user enter a positive number.Then call the function with input number. In this method it will find the digits of the number in the while loop using modulus "%" operator.

Output:

please enter the number: -345

enter a positive number only:1234

digit of number are:

4

3

2

1