Question

What is the entropy change of a 29.8 g ice cube that melts completely in a bucket of water whose temperature is just above the freezing point of water?

Answer 1

`\Delta S = 36.55 J/K`

Step-by-step explanation:

As we know that entropy change for phase conversion is given as

`\Delta S = (\Delta Q)/(T)`

Here we know that heat required to change the phase of the ice is given as

`\Delta Q = mL`

here we have

m = 29.8 g = 0.0298 kg

L = 335000 J/kg

now we have

`\Delta Q = 0.0298* 335000`

`\Delta Q = 9979.4 J`

also we know that temperature is approximately same as freezing temperature

so we have

`T = 273 k`

so here we have

`\Delta S = (9979.4)/(273)`

`\Delta S = 36.55 J/K`