Question

Copper sulfate is a blue solid that is used to control algae growth. Solutions of copper sulfate that come in contact with the surface of galvanized (zinc-plated) steel pails undergo the following reaction that forms copper metal on the zinc surface. How many grams of zinc would react with 454 g (1 lb) of copper sulfate (160 g/mol)?

Answer 1

185.5156 g

Step-by-step explanation:

The reaction of copper sulfate with zinc is shown below as:

`CuSO_4+Zn\rightarrow ZnSO_4+Cu`

Given that :

Amount of copper sulfate = 454 g

Molar mass of copper sulfate = 160 g/mol

The formula for the calculation of moles is shown below:

`moles = (Mass\ taken)/(Molar\ mass)`

Thus, moles are:

`moles= (454\ g)/(160\ g/mol)`

`moles\ of\ copper\ sulfate= 2.8375\ mol`

From the reaction,

1 mole of copper sulfate reacts with 1 mole of zinc

Thus,

2.8375 moles of copper sulfate reacts with 2.8375 moles of zinc

Moles of Zinc that should react = 2.8375 moles

Mass of zinc= moles×Molar mass

Molar mass of zinc = 65.38 g/mol

Mass of zinc = 2.8375 ×65.38 g = 185.5156 g