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In 1983, a pilot miscalculated the fuel requirement for Air Canada Fight 143 from Montreal to Edmonton. Halfway through the flight, the plane ran out of fuel because of an English-metric conversion error. Suppose that based on the distance and conditions, the flight would require at least 2.2 x 104 kg of fuel. The plane started off having 5, 756 liters in the tank when the pilot arrived. If there are 803 g of jet fuel in 1 liter, determine how much fuel (in liters) would be needed for a successful trip.

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Answer:

27,397.23 L would be needed for a successful trip.

Step-by-step explanation:

The problem gives us the density (ρ) of the fuel, by telling us that there are 803 g of fuel in 1 L, in which case:

ρ=
(mass)/(Volume)=(803g)/(1L)  =803(g)/(L)

The required mass of fuel is 2.2 * 10⁴ kg, we can convert this value into g:

2.2 * 10⁴ kg *
(1000g)/(1kg) = 2.2 * 10⁷ g

We calculate the required volume (V), using the mass and density:


803 g/L = (2.2*10^(7)g )/(V) \\V=(2.2*10^(7)g )/(803g/L)\\ V=27397.26 L

Thus 27,397.23 L would be needed for a successful trip.

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