Question

An aerosol can with a temperature of 292 K and a pressure of 1.25 atm was left outside in the sun on a hot summer day. The pressure inside the can rose to 1.33 atm. What was the resulting temperature in the can?

322K
1,600K
311K
274K

ik its not A

Answer 1

310.69K

Step-by-step explanation:

Given parameters:

Initial temperature T₁ = 292K

Initial pressure P₁ = 1.25atm

Final pressure P₂ = 1.33atm

Unknown:

Final temperature T₂ = ?

Solution

To find the unkown, we need to apply the combined gas law. From the combined gas law, it can be deduced that at constant volume, the pressure of a give mass or mole of gas varies directly with the absolute temperature.

Since the same aerosol can is heated, the volume is constant.

`(P_(1) )/(T_(1) )` =
`(P_(2) )/(T_(2) )`

Now, we have to make T₂ the subject of the formula:

T₂ =
`(P_(2)  x T_(1)  )/(P_(1) )`

T₂ =
`(1.33  x 292  )/(1.25 )` = 310.69K