Question

A squirrel runs along an overhead telephone wire that stretches from the top of one pole to the next. It is initially at position xi=3.37 mxi=3.37 m , as measured from the center of the wire segment. It then undergoes a displacement of Δx=−6.83 mΔx=−6.83 m . What is the squirrel's final position xfxf ?

Answer 1

- 3.46 m

Step-by-step explanation:

initial position, xi = 3.37 m

displacement, Δx = - 6.83 m

Let the final position is xf.

So, displacement = final position - initial position

Δx = xf - xi

- 6.83 = xf - 3.37

xf = 3.37- 6.83

xf = - 3.46 m

Thus, the final position of the squirrel is - 3.46 m.