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While standing on the roof of a building, a child tosses a tennis ball with an initial speed of 13 m/s at an angle of 35° below the horizontal. The ball lands on the ground 2.6 s later. How tall, in meters, is the building?

User Ozzymado
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1 Answer

6 votes

Answer:

building height is 52.52 m

Step-by-step explanation:

given data

initial speed v = 13 m/s

angle = 35°

time = 2.6 s

to find out

how tall is building

solution

we consider here h is height of building

so

initial velocity at angle 35 is express as

u = v sin(θ) ...........1

u = 13 sin35 = 7.45 m/s

so

by distance formula

h = ut + 1/2 at² ...........2

h = 7.45 ( 2.6) + 1/2 × (9.81) × (2.6)²

h = 52.52 m

so building height is 52.52 m

User Xxxxx
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