Answer:
The maximum height that the rocket reaches is 645.5 m.
Step-by-step explanation:
Given that,
Mass = 10000 kg
Acceleration = 2.25 m/s²
Distance = 525 m
We need to calculate the velocity
Using equation of motion

Put the value in the equation



We need to calculate the maximum height with initial velocity
Using equation of motion


Put the value in the equation


The total height reached by the rocket is



Hence, The maximum height that the rocket reaches is 645.5 m.