Question

a.) The diameter of a uranium atom is 3.50 Å . Express the radius of a uranium atom in both meters and nanometers. b.) How many uranium atoms would have to be lined up side by side to span 2.40 mm? c.) If the atom is assumed to be a sphere, what is the volume in cubic centimeters ( cm^3 ) of a single uranium atom?

Answer 1

Th answer to your question is:

a) 3.5 x10⁻¹⁰ meters; 0.35 nm

b) 6857142.86 atoms

c) Volume = 2.06 x 10⁻²³ cm³

Step-by-step explanation:

a) data

Uranium atoms = 3.5A°

meters

1 A° ---------------- 1 x 10 ⁻¹⁰ m

3.5A° --------------- x

x = 3.5(1 x10⁻¹⁰)/ 1 = 3.5 x10⁻¹⁰ meters

1 A° ------------------ 0.1 nm

3.5 A° ---------------- 0.35 nm

b) 2.4 mm

Divide 2,40 mm / uranium diameter

But, first convert 3,5A° to mm = 3.5 x 10⁻⁷ mm

# of uranium atoms = 2.4 / 3.5 x 10⁻⁷ = 6857142.86

c) volume in cubic cm

Convert 3.5A° to cm = 3.5 x 10⁻⁸

Volume = 4/3 πr³ = (4/3) (3.14)(1.7 x10⁻⁸)³

Volume = 2.06 x 10⁻²³ cm³