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What is the density of a 19.3-gram object that displaces 12 cubed centimeters of water

User Dcsan
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1 Answer

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Answer:

1.608 g/cm3

Step-by-step explanation:

Formula:

D=m/v

d= density

m= mass

v= volume

Given data:

Mass= 19.3 g

Volume= 12 cm3

The volume of water displaces by object is 12 cm³ which means that object hold the volume of 12 cm³

Now we will put the values in formula:

D=19.3 g/ 12 cm3= 1.608 g/cm3

so the density of object is 1.608 g/cm3

User Shivanshu Goyal
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