Question

A house is losing heat at a rate of 1600 kJ/h per °C temperature difference between the indoor and the outdoor temperatures. Express the rate of heat loss from this house per K, °F, and R difference between the indoor and the outdoor temperature.

Answer 1

1600 kJ/h per K, 888.88 kJ/h per °F and 888.88kJ/h per R

Step-by-step explanation:

We make use of relations between temperature scales with respect to degrees celsius:

`1 K= 1^(\circ)C+273\\1^(\circ)F= (1^(\circ)C*1.8)+32\\1 R= (1^(\circ)C*1.8)+491.67`

This means that a change in one degree celsius is equivalent to a change of one kelvin, while for a degree farenheit and rankine this is equivalent to a change of 1.8 on both scales.

So:

`(Q)/(\Delta T(K))=(Q)/(\Delta T(^\circ C))=1600 (kJ)/(h) per K\\(Q)/(\Delta T(^\circ F))=(Q)/(\Delta T(^\circ C*1.8))=888.88 (kJ)/(h) per ^\circ F\\(Q)/(\Delta T(R))=(Q)/(\Delta T(^\circ C*1.8))=888.88 (kJ)/(h) per R`