Question

Select the correct answer. For what value of x is sin x = cos 19º, where 0°< x < 90°? OA. 38° ° O B. 71° OC. 26° O D. 19°​

Answer 1

x = 71°

Option B is correct answer.

Explanation:

We need to find for what value of x is
`sin\: x = cos 19^(\circ)`, where 0°< x < 90°?

Solving:

`sin\: x = cos\: 19^(\circ)\\Finding \:cos\: 19^(\circ)=0.94551\\Putting\:value:\\sin\:x=0.94551\\Now\:taking\:sin\:inverse\\x=sin^(-1)(0.94551)\\x=71^(\circ)`

So, we get x = 71°

Option B is correct answer.