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For some constants a and b let \[f(x) = \left\{ \begin{array}{cl} 9 - 2x & \text{if } x \le 3, \\ ax + b & \text{if } x > 3. \end{array} \right.\]The function f has the property that f(f(x)) = x for all x. What is a + b?

User Telos
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1 Answer

3 votes

Answer:

The value of a+b is 4.

Explanation:

The given function is


\[f(x) = \left\{ \begin{array}{cl} 9 - 2x & \text{if } x \le 3, \\ ax + b & \text{if } x > 3. \end{array} \right.\]

It is given that for some constants a and b the function f has the property that f(f(x))=x for all x.

For x≤3,


f(x)=9-2x

For x>3,


f(x)=ax+b

At x=0,


f(0)=9-2(0)=9


f(f(0))=f(9)\Rightarrow a(9)+b=9a+b

Using property f(f(x))=x,


f(f(0))=0


9a+b=0 .... (1)

At x=1,


f(1)=9-2(1)=7


f(f(1))=f(7)\Rightarrow a(7)+b=7a+b

Using property f(f(x))=x,


f(f(1))=1


7a+b=1 .... (2)

Subtract equation (2) from equation (1).


9a+b-(7a+b)=0-1


2a=-1

Divide both sides by 2.


a=-(1)/(2)

Substitute this value in equation (1).


9(-(1)/(2))+b=0


b=(9)/(2)

The value of a is
-(1)/(2) and value of b is
(9)/(2). The value of a+b is


a+b=-(1)/(2)+(9)/(2)


a+b=4

Therefore the value of a+b is 4.

User Federico Piragua
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