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A random sample of 50 consumers taste tested a new snack food. Their responses were coded (0: do not like; 1: like, 2: indifferent) and recorded below: a. Test H0: p = 0.5 against Ha: p > 0.5, where p is the proportion of customers who do not like the snack food (n=17). Use α = 0.10. b. Find the observed significance level of your test.

1 Answer

5 votes

Answer:

The level of significance observed is 0.99154

Explanation:

Assuming that in a sample of size 50 people stated that they do not like the snack (p = 17/50), you have:

Proportion in the null hypothesis
\pi_0=0.5

Sample size
n=50

Sample proportion
p=17/50=0.34

The expression for the calculated statistic is:


= ((p - \pi_0)√(n))/(√(\pi_0(1-\pi_0)))


= ((0.34 - 0.5)√(50))/(√(0.34(0.66))) = -2,38833

The level of significance observed is obtained from the value of the statistic calculated:


P(Z>Z_(calculated)) = 0.99154

User Jared Allard
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