Answer:
There are 40 nickels, 14 quarters and 20 dimes.
Explanation:
A change drawer contains $7.50
Let the number of quarters in the drawer = q
let the number of nickels in the drawer = n
and number of dimes = d
So, (0.25q + 0.05n + 0.10d) = 7.5
By dividing the equation by 0.50
5q + n + 2d = 150 ---------(1)
Now statement says " There are twice as nickels as dimes"
n = 2d -------(2)
And "the number of dimes and quarters sum to 34"
d + q = 34 -------(3)
We replace n = 2d from equation (2) in equation (1)
5q + 2d + 2d = 150
5q + 4d = 150 ---------(4)
Multiply equation (3) by 4 and subtract it from equation (4)
(5q + 4d) - 4(d + q) = 150 - 34×4
5q - 4q + 4d - 4d = 150 - 136
q = 14
We plug in the value of q in equation (3)
d + 14 = 34
d = 34 - 14
d = 20
Since n = 2d
So n = 2×20
n = 40
Therefore, there are 40 nickels, 14 quarters and 20 dimes.