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10x^5+5x^3-14x^2-7
factor expression​

User PCoelho
by
5.1k points

1 Answer

3 votes

Answer:

Explanation:

10x5+5x3-14x2-7

(5x3 - 7) • (2x2 + 1)

Step by step solution :

Step 1 :

Equation at the end of step 1 :

(((10•(x5))+(5•(x3)))-(2•7x2))-7

Step 2 :

Equation at the end of step 2 :

(((10 • (x5)) + 5x3) - (2•7x2)) - 7

Step 3 :

Equation at the end of step 3 :

(((2•5x5) + 5x3) - (2•7x2)) - 7

Step 4 :

Checking for a perfect cube :

4.1 10x5+5x3-14x2-7 is not a perfect cube

Trying to factor by pulling out :

4.2 Factoring: 10x5+5x3-14x2-7

Thoughtfully split the expression at hand into groups, each group having two terms :

Group 1: -14x2-7

Group 2: 10x5+5x3

Pull out from each group separately :

Group 1: (2x2+1) • (-7)

Group 2: (2x2+1) • (5x3)

-------------------

Add up the two groups :

(2x2+1) • (5x3-7)

Which is the desired factorization

User Risheek Mittal
by
5.2k points