Quick help guys thanks :)

asked Oct 11, 2020 210k views

1 vote

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2 votes

Answer:

$\large\boxed{t^(-58)u^(-88)v^(-71)w^(-1)}$

Explanation:

$(tuv^4w^0)/(t^(59)u^(89)v^(75)w)\qquad\text{use}\ (a^n)/(a^m)=a^(n-m)\\\\=t^(1-59)u^(1-89)v^(4-75)w^(0-1)=t^(-58)u^(-88)v^(-71)w^(-1)$

Majorie answered Oct 15, 2020

5.5k points

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