Answer:
see below
Explanation:
3. The answers in the image below are in "interval notation". In set notation, they might be ...
increasing: {x∈ℝ: -2 < x < 0 ∪ 2 < x}
decreasing: {x∈ℝ: 0 < x < 2}
positive: {x∈ℝ: -4 ≤ x < 1.5 ∪ 3 < x}
negative: {x∈ℝ: 1.5 < x < 3}
domain: {x∈ℝ: x ≥ -4}
range: {x∈ℝ: x ≥ -3}
y-intercept: y ∈ {2}
x-intercepts: x ∈ {1.5, 3}
relative minimum: (x, y) ∈ {(2, -3)}
relative maximum: (x, y) ∈ {(0, 2)}
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4. Answers are in the image below.
The function is increasing where its slope is positive, decreasing where its slope is negative. Where the slope changes sign, there may be a point where the slope is 0 or undefined. The function is neither increasing nor decreasing there, so those points are not part of the intervals for increasing or decreasing.
The function is positive when it is above the x-axis, negative when it is below the x-axis. The function is neither positive nor negative where it is on the x-axis or where it is undefined.
The domain is the horizontal extent of the function. Any points where the function is undefined are excluded.
The range is the vertical extent of the function, all of the y-values where the function output is defined. Here, m(2) is not defined, so y=-7 is not an output at that point. However, y=7 is an output for m(-14 2/3). Likewise, m(9) does not have an output of 0, but m(3) does, so 0 is part of the range.
X- and y-intercepts are where the graph intersects the x- or y-axis, respectively. M(x) is undefined at (9, 0), so there is no x-intercept there.
A relative minimum is any point where the y-values increase on either side of the point. For m(x), the function is undefined at its relative minima, so it cannot be said to have any.
A relative maximum is any point where the y-value decreases on either side of the point. M(x) has one at the vertex of the parabolic segment.