Answer: The answer is: 62.5 % (left over).
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Explanation:
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;
Change "(1/4)" to: "(?/8)" ;
What is "(?)" ? ;
→ (1/4) = (?/8) ;
notice the denominators;
(1/4) = (?/8) ; In the first fraction, how does the "denominator", "4" ; turn to "8" ? Specifically, since we dealing with "fractions", what number do we multiply "4" by, to get: "8" ??? ;
→ " 4 * ? = 8 " ?? ;
→ " 8 ÷ 4 = ? " ;
= 2 ;
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so " 1/4 = ?/8 " ;
Since we multiply the denominator, "4" ; by "2" , to get:
"8" (the denominator in the other fraction);
we multiply the numerator, "1" ; by "2" ; to get:
"2" (the denominator in the other fraction):
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→ "
;
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Now, the amount of the pizza that "you" ate is: "(2/8)" ;
The amount of the pizza eaten by "your dog" is: "(1/8)" ;
Let's add up the amount of pizza eaten:
.
The total amount of the pizza would be: "
" .
Note: "
= 8 ÷ 8 = 1 whole [pizza].
To find the amount left over, subtract the amount eaten; "(3/8)" ; from the whole pizza; "(8/8)" ; as follows:
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→
.
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Now, the question asks, what percent is left over? ;
So, we convert "(5/8)" into a percentage;
Change "(5/8)" to: "(?/100)" ;
→ Notice the denominators;
(5/8) = (?/100) ; In the first fraction, how does the "denominator", "8" ; turn to "100" ? Specifically, since we dealing with "fractions", what number do we multiply "8" by, to get: "100" ??? ;
→ " 8 * ? = 100 " ?? ;
→ " 100 ÷ 8 = ? " ;
= 12.5 ;
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so " 5/8 = ?/100 " ;
Since we multiply the denominator, "8" ; by "12.5" , to get:
"100" (the denominator in the other fraction);
we multiply the numerator, "5" ; by "12.5" ; to get:
"2" (the denominator in the other fraction):
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→ "
;
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→ [tex]\frac{62.5}{100} = 62.5 % .
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Hope this helpful to you!
Wishing you the best!
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