Question

From this reaction, N2(g) + 2H2(g) ---> 2NH3(g)

If 20 grams of products are formed, how many grams of reactants did you start with?

Answer 1

The answer to your question is:

16.47 g of N2 and 3.52 g of H2

Step-by-step explanation:

Data

20 g of products were obtain.

Process

AW N2 = 28 g

AW H2 = 2g

MW NH3 = 17 g

N2(g) + 3H2(g) ---> 2NH3(g)

28g 3(2)g 2(17) g

20 g

N2

28 g N2 ------------------- 34 g of NH3

x -------------------- 20 g of NH3

x = 20(28)/34 = 16.47 g of N2

H2 6 g of H2 ------------------- 34 g of NH3

x 20 g of NH3

x = 20(6)/34 = 3.52 g of H2

Total mass = 16.47 g of N2 + 3.52 g of H2 = 19.99 g ≈ 20 g