Question

A bullet in a gun is accelerated from the firing chamber to the end of the barrel at an average rate of 5.80 ✕ 105 m/s2 for 9.60 ✕ 10−4 s. What is its muzzle velocity (in m/s) (that is, its final velocity)? (Enter the magnitude.)

Answer 1

Final velocity will be 556.8 m/sec

Step-by-step explanation:

We have given the average rate of change of velocity that is
`a=5.8* 10^5m/sec`

Time
`t=9.6* 10^(-4)sec`

Initial velocity of bullet will be zero that is u=0

Now according to first law of motion

v=u+at, here v is final velocity, u is initial velocity and t is time

So
`v=0+5.8* 10^5* 9.6* 10^(-4)=556.8m/sec`