The diameter of an ice skating rink is 44 feet. In terms of π, what is the area of the rink to the nearest square yard? (9 ft2 = 1 yd2)

Question

asked Jun 7, 2020 53.5k views

2 Answers

Grebulon · Answer 1 · 2020-06-12T16:21:01+0000

Answer: Our required area is 54π sq. yd.

Explanation:

Since we have given that

Diameter of an ice skating = 44 feet

Radius of an ice skating = 22 feet

as we know the formula for area :

Area would be

$\pi r^2\\\\=\pi * 22^2\\\\=484\pi\ ft^2$

As we know that

9 sq ft = 1 sq yd

So, it becomes,

$(484\pi)/(9)=53.77\pi\ yd^2\approx 54\pi\ yd^2$

Hence, our required area is 54π sq. yd.