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4 votes
PLEASE HELP What is the equation in standard form of a parabola with a focus of (-3,2) and a directrix of y=4.

2 Answers

4 votes

Answer:

i think this will help (x - (-3))^2 = 4(2)(y - 0)

(x + 3)^2 = 8y

Explanation:

User Azhpo
by
5.9k points
4 votes

Graphing y = 4 and the focus, we clearly see that the equation we need has the form (x - h)^2 = 4a(y - k).

We need to find a, h and k.

The focus is half way between the vertex and directrix.

You know that y = 4 is 2 units away from the focus and the focus is 2 units down from the focus. So, our vertex is (-3, 0).

From the vertex to the directrix, there are 4 units. Half that distance is the value of a. So, a = 2.

We have all that is needed to form our equation.

(x - (-3))^2 = 4(2)(y - 0)

(x + 3)^2 = 8y

Done.

User Venk K
by
6.0k points
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