Answers with explanations:
Problem 2-
First we have to insert our numbers into the equation. So we would have
l2l-l-7l
The ll bars mean to find the absolute value. Absolute value is how many spaces it is between that number and zero. So we can simply this to
2-7=-5
Problem 3-
First, we have to insert our numbers into the problem.
2(-2)^3(3)
Using PEMDAS or order of operations, we solve the exponent first and simplify from there
2(-8)(3)
(-16)(3)
(-48)
The answer is -48
Problem 4-
Again, we have to input the numbers into the equation.
(4^2-4(-3))/2
(16-4(-3))/2
(16+12)/2
(28)/2
14
The answer is 14
Problem 5-
(3)(-1)-(-1^2)
(3)(-1)-(1)
-3-1
-4
The answer is -4
Problem 7-
l-3-4l- -3^2
l-3-4l- +9
l-7| - +9
7-+9
-2
The answer is -2
Problem 8-
3(-3)^2-4|-3|+6
3(9)-4|-3|+6
27-4|-3|+6
27-12+6
21