Question

Problem Set:

At the sixth-grade school dance, there are 132 boys, 89 girls, and 14 adults.

a. Write the ratio of the number of boys to the number of girls.

b. Write the same ratio using another form (A: B vs. A to B).

c. Write the ratio of the number of boys to the number of adults.

d. Write the same ratio using another form.

*Answer A-D

Answer 1

Part a)
`(132)/(89)`

Part b) 132:89 vs 132 to 89

Part c)
`(66)/(7)`

Part d) 66:7 vs 66 to 7

Explanation:

Let

x ----> the number of boys

y ----> the number girls

z ----> the number of adults

we have

x=132, y=89, z=14

Part a) Write the ratio of the number of boys to the number of girls.

To find the ratio of the number of boys to the number of girls, divide the number of boys by the number of girls

so

`(x)/(y)`

substitute

`(132)/(89)`

Part b) Write the same ratio using another form (A: B vs. A to B)

we have

`(132)/(89)`

The other form is

132:89 vs 132 to 89

Part c) Write the ratio of the number of boys to the number of adults

To find the ratio of the number of boys to the number of adults, divide the number of boys by the number of adults

so

`(x)/(z)`

substitute

`(132)/(14)`

Simplify

`(66)/(7)`

Part d) Write the same ratio using another form

The other form is

66:7 vs 66 to 7