Question

Consider a charged particle at a pointS whose coordinates are (8 m, 4 m, 10 m). We would like to find the electric field vector at a point P whose coordinates are (7 m, 2 m, 6 m). The "unit vector" r ^ is a vector that points from S to P that has length of 1 (or "unity"). What is its y component, in meters

Answer 1

E=
`k*(q)/(21)*u`

`u=(1)/(√(21)) *(-1,-2,-4)m`

`u_(y)=(-2)/(√(21)) m`

Step-by-step explanation:

q: particle's charge

k: coulomb constant

E=E*u

r=r*u

r=distancia vectorial entre P y S

r=distancia escalar entre P y S

E: Electric field vector

E: magnitud of magnetic field vector

u: unit vector radial

then:

`E=k*q/r^(2)`

r=r*u

r=P-S=(-1,-2,-4)m

`r^(2)=(Magnitude(P-S))^2=(-1)^2+(-2)^2+(-4)^2=21`

`r=√(21)`

E=
`k*(q)/(21)*u`

u=r/r=
`(1)/(√(21)) *(-1,-2,-4)m`

`u_(y)=(-2)/(√(21)) m`