Answer:
10 m/s
Step-by-step explanation:
u = 20 m/s
v = 0 m/s
t = 5.8 s
Let a be the acceleration and s be the distance traveled by the car in time t.
use first equation of motion
v = u + a t
0 = 20 + a x 5.8
a = -3.45 m/s^2
Use third equation of motion
![v^(2)=u^(2)+2as](https://img.qammunity.org/2020/formulas/physics/high-school/obiz6wq8wm4hlxtgrpgte68bf8o00xokbq.png)
![0^(2)=20^(2)-2 *3.45 * s](https://img.qammunity.org/2020/formulas/physics/high-school/pv0z7b3v33otn4rt1t2phlyg2cdgdjn1mu.png)
s = 58 m
The average speed is defined as the ratio of distance traveled to the time taken.
![Average speed = (58)/(5.8) = 10 m/s](https://img.qammunity.org/2020/formulas/physics/high-school/e3m63k7ali260i7vi7s2zm7l3f9fd7642n.png)
thus, the average speed of the car is 10 m/s.