Answer:
The second statement is true: If the concentration of Y is increased by a factor of 1.5, the rate will increase by a factor of 2.25.
Step-by-step explanation:
Hi there!
Let´s write the rate law for the original reaction and the reaction with X increased by 1.5:
rate 1 =k [X][Y]²
rate 2 = k[1.5 X][Y]²
Now we have to demonstrate if rate 2 = 2.25 rate 1
Let´s do the cocient between the two rates:
rate 2/ rate 1
if rate 2 = 2.25 rate 1
Then,
rate 2 / rate 1 = 2.25 rate 1 / rate 1 = 2.25
Let´s see if this is true using the expressions for the rate law:
rate 2 / rate 1
k[1.5 X][Y]² / k [X][Y]² = 1.5 k [X][Y]² / k[X][Y]² = 1.5
2.25 ≠ 1.5
Then the first statement is false.
Now let´s write the two expressions of the rate law, but this time Y will be increased by 1.5:
rate 1 = k[X][Y]²
rate 2 = k[X][1.5Y]²
Again let´s divide both expressions to see if the result is 2.25
rate 2 / rate 1
k[X][1.5Y]²/ k [X][Y]²
(distributing the exponent)
(1.5)²k [X][Y]² / k [X][Y]² = (1.5)² = 2.25
Then the second statement is true!