Question

Given triangle ABC with coordinates A(−6, 4), B(−6, 1), and C(−8, 0), and its image A′B′C′ with A′(−2, 0), B′(−5, 0), and C′(−6, −2), find the line of reflection.

The line of reflection is at y=?

Answer 1

The line of reflection is at y = x+6.

Explanation:

The perpendicular bisector of AA' is a line with slope 1 through the midpoint of AA', which is (-4, 2). In point-slope form, the equation is ...

y = 1(x +4) +2

y = x + 6 . . . . . . . line of reflection