Question

Three vectors →a, →b, and →c each have a magnitude of 50 m and lie in an xy plane. Their directions relative to the positive direction of the x axis are 30°, 195°, and 315°, respectively. What are (a) the magnitude and (b) the angle of the vector →a+→b+→c and (c) the magnitude and (d) the angle of →a−→b+→c? What are the (e) magnitude and (f) angle of a fourth vector →d such that (→a+→b)−(→c+→d)=0 ?

Answer 1

a) 38.27 b) 322.5°

c) 126.99 d) 1.17°

e) 62.27 e) 139.6°

Step-by-step explanation:

First of all we have to convert the coordinates into rectangular coordinates, so:

a=( 43.3 , 25)

b=( -48.3 , -12.94)

c=( 35.36 , -35.36)

Now we can do the math easier (x coordinate with x coordinate, and y coordinate with y coordinate):

1.) a+b+c=( 30.36 , -23.3) = 38.27 < 322.5°

2.) a-b+c=( 126.96 , 2.6) = 126.99 < 1.17°

3.) (a+b) - (c+d)=0 Solving for d:

d=(a+b) - c = ( -40.36 , 47.42) = 62.27 < 139.6°