Question

The position of a particle moving under uniform acceleration is some function of time and the acceleration. Suppose we write this position as x = kamtn, where k is a dimensionless constant. Show by dimensional analysis that this expression is satisfied if m = 1 and n = 2. (Submit a file with a maximum size of 1 MB.)

Answer 1

Step-by-step explanation:

`x = k* a^m* t^n`

k is constant , it is dimension is zero. Using dimensional unit , we cal write the relation as follows

L =
`(LT^(-2))^m(T)^n`

=
`L^mT^(-2m+n)`

Equating power of like items

m=1

-2m+n = 0

n = 2