Answer:
![a=(v_(f)-v_(o) )/(t_(f)-t_(o) ) =((7-22)(m)/(s) )/(5s-0s) =-3(m)/(s^(2) )](https://img.qammunity.org/2020/formulas/physics/college/uyin26d702mfltsnrt5db0hczhyp0sisjj.png)
Step-by-step explanation:
We know that the initial velocity is 22 m/s
The final velocity after applying the brakes is 7 m/s, and the time that takes it to break is 5 seconds
We know that the concept of acceleration is the change of velocity in time
![a=(v_(f)-v_(o) )/(t_(f)-t_(o) ) =((7-22)(m)/(s) )/(5s-0s) =-3(m)/(s^(2) )](https://img.qammunity.org/2020/formulas/physics/college/uyin26d702mfltsnrt5db0hczhyp0sisjj.png)
The answer is negative since the car is slowing down