Question

A baseball pitcher throws a baseball with a speed of 42 m/s . In throwing the baseball, the pitcher accelerates it through a displacement of about 3.5 m, from behind the body to the point where it is released.

Answer 1

a = 252 m / s²

Step-by-step explanation:

The initial speed Vο = 0

The speed of baseball with witch it is thrown Vf = 42 m/s

Displacement covered = 3.5 m

Hence acceleration will be constant at this moment, so as per the equation of constant acceleration : ( Vf² - Vο² ) / 2d = a

a = 252 m / s²