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Use vectors to decide whether the triangle with vertices P(1, −2, −1), Q(2, 1, −3), and R(6, −1, −4) is right-angled. Yes, it is right-angled. No, it is not right-angled.

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Answer:

Yes, it is right-angled

Step-by-step explanation:

Two vectors are orthogonal if the scalar product between them is zero. Then, we will match each pair of vertices with a vector, wich is formed with the following formula:

Given two points A and B, the vector going from A to B is


AB=B-A=(B_(x)-A_(x),B_(y)-A_(y),B_(z) -A_(z))

So, we calculate each component separately.


PQ=Q-P=(2-1,1-(-2),-3-(-1))=(1,3,-2)


QR=R-Q=(6-2,-1-1,-4-(-3))=(4,-2,-1)


RP=P-R=(1-6,-2-(-1),-1-(-4))=(-5,-1,3)

Finally, using the scalar product formula


A*B=A_(x)* B_(x)+ A_(y)* B_(y)+ A_(z)* B_(z)

we see if the products is zero


PQ*QR=1*4+3(-2)+(-2)*(-1)=0

In this case we don't even have to calculate the other products as we've found that PQ and QR form a right angle.

User Jafar Shemshadi
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