Answer:
The equations that represent the reflected function are
![f(x)=5((1)/(5))^(-x)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/mntmk5rw1q3th6emdhjui59n9mfttoatae.png)
![f(x)=5(5)^(x)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/c1qh4w4nyyo4agy4jfiick5kxm7astahva.png)
Explanation:
The correct question in the attached figure
we have the function
![f(x)=5((1)/(5))^(x)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/j3k0i4k2nwve78mkex3boe068qcs21tye0.png)
we know that
A reflection across the y-axis interchanges positive x-values with negative x-values, swapping x and −x.
therefore
![f(−x) = f(x).](https://img.qammunity.org/2020/formulas/mathematics/middle-school/2k3hqnh84nobgv73vhqo9wcq9mxhlail5x.png)
The reflection of the given function across the y-axis will be equal to
(Remember interchanges positive x-values with negative x-values)
![f(x)=5((1)/(5))^(-x)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/mntmk5rw1q3th6emdhjui59n9mfttoatae.png)
An equivalent form will be
![f(x)=5((1)/(5))^((-1)(x))=5[((1)/(5))^(-1))]^(x)=5(5)^(x)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/dgjyemjqsfz4z3odpgia9k87wvnjlqbet9.png)
therefore
The equations that represent the reflected function are
![f(x)=5((1)/(5))^(-x)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/mntmk5rw1q3th6emdhjui59n9mfttoatae.png)
![f(x)=5(5)^(x)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/c1qh4w4nyyo4agy4jfiick5kxm7astahva.png)