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Answer for the square root(5x-9)+1=x

User Clarenswd
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\bf √(5x-9)+1=x\implies √(5x-9)=x-1\implies 5x-9 = (x-1)^2 \\\\\\ 5x-9=\stackrel{\mathbb{FOIL}}{x^2-2x+1}\implies 5x=x^2-2x+10\implies 0=x^2-7x+10 \\\\\\ 0=(x-5)(x-2)\implies x= \begin{cases} 5\\ 2 \end{cases}

User Enkode
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