Question

Solve for x and show your steps. Is the solution extraneous? Check your work to show how you determined if the solution is extraneous or not. The square root of the quantity 4 x minus 3 end quantity equals 5.

Answer 1

• x=7

Explanation:

At first let's understanding the situation

The square root of the quantity 4 x minus 3 end quantity equals 5.

we have to find the value if x.

Solution:-

`√((4x-3))=5`

By squaring on both sides

`{√((4x-3))}^(2)=5^(2)\\\\\\4x-3=25\\\\4x=25+3\\\\4x=28\\\\x=7`

Answer 2

x= 7.

Explanation:

1. Write the expression.

`√(4x-3)=5`

2. Take the square root of both sides of the equation.

`(√(4x-3))^(2) =5^(2) \\ \\4x-3=25`

3. Sum 3 to both sides of the equation.

`4x-3+3=25+3\\ \\4x=28`

4. Divide by 4 on both sides of the equation.

`(4x)/(4) =(28)/(4) \\ \\x=7`

5. Express your result.

x= 7.