Question

Earth orbits around the Sun at an average speed of 30 km/s. How far does the Earth move in a year (3.16 x 107 s) as it revolves around the Sun? Express your answer in kilometers using the correct number of significant figures

Answer 1

The Earth moves 9.48 × 10⁸ kilometers in a year as it revolves around the Sun, calculated by multiplying the average speed of 30 km/s by the time of one year, 3.16 × 10⁷ seconds.

Step-by-step explanation:

To calculate the distance that Earth moves in a year as it revolves around the Sun, we can use the formula for distance traveled, which is distance = speed × time. Given that Earth orbits around the Sun at an average speed of 30 kilometers per second (km/s) and the time it takes for one orbit is 3.16 × 107 seconds, the calculation would be:

30 km/s × 3.16 × 107 s = distance

Distance = 30 × 3.16 × 107 km

Distance = 94.8 × 107 km

Distance = 9.48 × 108 km

The Earth moves 9.48 × 108 kilometers in a year as it revolves around the Sun, using the correct number of significant figures.

Answer 2

`d=v*t=(30(km)/(s))(3.16x10^(7))=9.48x10^(8)km`

Step-by-step explanation:

Our knowable variables are velocity and time

`v=30 (km)/(s)`

`t=3.16x10^(7)s`

We know that
`v=(d)/(t)`

So, with the data that we have we can calculate distance

`d=v*t=(30(km)/(s))(3.16x10^(7))=9.48x10^(8)km`