Question

According to Archimedes’ principle, the mass of a floating object equals themass of the fluid displaced by the object. A swimmer is floating ina nearby pool; 95% of her body’s volume is in the water while 5% of herbody’s volume is above water. Determine the density of the swimmer’s body.The density of water is Does your answer make sense? Whyor why not?

Answer 1

Answer: 950 Kg/m^3

Explanation: We can deduce from the Archimedes principle that there is a relation between the density and the volumes displaced, as follows:

Density*Volume= Mass

So for equilibrium Density of body= Density of water *Vw/Vb

Being Vw/Vb the relation between the displaced water and the body volume, and given the water density as 1000 Kg/m^3 we got:

Density(B)= 0.95 * 1000 Kg/m^3.