Question

Plz help quick How do you do this problem

Answer 1

Answer:
`(pr)/(675)`

Explanation:

1. cant have a negative exponent
2. 
   `(1)/((3p^(-1) r)^3(5pr^(-2) )^2) \\`
3. split up (3p^-1 r)^3
4. rewrite that part of the equation
5. 
   `(1)/(((3)/(p) )^(3) r^(3) )`
6. raise 3 to the power of 3 = 27
7. p to the power of 3 =
   `p^(3)`
8. Next part of the equation
9. 
   `(5p)^(2)`
10. expand that
11. 
    `5^(2) p^(2)`
12. simplfy
13. 
    `25p^(2)`
14. Next part of the equation
15. 
    `(r^(-2))^(2)`
16. multiply the exponents
17. 
    `r^(-4)`
18. rewrite the equation
19. 
    `(1)/((27)/(p^(3) )r^(3) (25p^(2))(1)/(r^(4) ) )`
20. combine
    `(27)/(p^(3) ) , and , r^(3)` =
    `(27r^(3) )/(p^(3) )`
21. combine 25 and
    `(27r^(3) )/(p^(3) )`
22. Multiply
23. 
    `(675r^(3) )/(p^(3) )`
24. combine
    `(675r^(3) )/(p^(3) )` and
    `p^(2)`
25. 
    `(675r^(3)p^(2) )/(p^(3) )`
26. multiply
    `(675r^(3)p^(2) )/(p^(3) )` and
    `(1)/(r^(4) )`
27. 
    `(1)/((675r^(3)p^(2) )/(p^(3)r^(4) ))`
28. cancel the common factors and factor everything out
29. 
    `r^(3)` comes out of
    `{675r^(3)p^(2) }`
30. 
    `r^(3)` can also come out of
    `p^(3) r^(4)`
31. Rewrite as
    `(1)/((675p^(2) )/(p^(3) r) )`
32. cancel the common factor of
    `p^(2)` and
    `p^(3)`
33. factor
    `p^(2)` out of
    `675p^(2)` by mulitiplying
34. factor
    `p^(2)` out of
    `{p^(3) r} }`
35. cancel the common factor
36. rewrite the expression
37. 
    `(1)/((675)/(pr) )`
38. and then multiply the numerator and denominator
39. and you get the answer