Answer:
Step-by-step explanation:
So, the formula for the compound should be:
![XCl_(6)](https://img.qammunity.org/2020/formulas/chemistry/high-school/76rh3rl3pc9ayt42b4o5zv4htdraonko6g.png)
Now we assume that we have 1 mol of substance, so we can make calculations to know the molar mass of element X, as follows:
![M_(Cl)=35.45g/mol\\](https://img.qammunity.org/2020/formulas/chemistry/high-school/t985ydum6iit4rnml01opghlq4gpvjvk6x.png)
So we have that 6 moles weight 212.7g, and we can make a rule of three to know the weight of compound X:
![212.7g\rightarrow 86.9\%\\x\rightarrow 13.1\%\\\\x=(212.7g*13.1)/(86.9) =32.06g](https://img.qammunity.org/2020/formulas/chemistry/high-school/2t7sdkvv9kvoo0o760msr4zd3q83g5p7rn.png)
As we used 1 mol, we know that the molar mass is 32.06g/mol
So the element has a molar mass of 32.06 g/mol and an oxidation state of +6, with this information, we can assure that the element X is sulfur, so the compound is
![SCl_(6)](https://img.qammunity.org/2020/formulas/chemistry/high-school/y60bvs007voh43y1zqhkstzbjfrwa5x8hj.png)