Answer:
304.42 cc
Step-by-step explanation:
When the aluminum expands the markings will be further apart. If the 300 cc mark was at a distance l0 of the origin at 20 C, at 100 C it will be
l = l0 * (1 + a * (t - t0))
l = l0 * (1 + 23*10^-6 * (100 - 20))
l = l0 * 1.0018
The volume of water would have expanded by
V = V0 (1 + a * (t - t0))
V = 300 (1 + 2.07*10^-4 * (100 - 20))
V = 304.968 cc
Since the markings expanded they would measure
304.968/1.0018 = 304.42 cc